Temecula Named Among America's Safest Cities

TEMECULA, CA — Temecula was recently named among the 50 safest cities in the United States, according to financial news site 24/7 Wall St.

Our city finished 19 on the overall list, with the following statistics:

• 2018 Violent Crime Rate: 119.4 per 100,000 people
• 2018 Homicides: 0
• Poverty Rate: 6.8%
• 2018 Unemployment Rate: 3.5%

"The typical household in Temecula earns $87,115 a year, about $29,000 more than the U.S. median annual household income," the report states in part. "Cities with better economic conditions tend to have less violent crime. In Temecula, there were just 119 violent crimes reported per 100,000 residents in 2018, less than one-third the national violent crime rate of 369 per 100,000 and among the lowest rate of any city nationwide."

Nearby Murrieta came in at number 3 on the list and Corona was number 31.

To find the 50 safest cities in the United States, 24/7 Wall St. went through the FBI’s 2018 Uniform Crime Report and found the total number and rates of murder, non-negilent manslaughter, rape, robbery and aggravated assault.

The site also used the U.S. Census Bureau’s 2017 American Community Survey to find the median household income and poverty rates for the cities.

Irvine ranked as the safest city in the nation, followed by Naperville, Illinois.

“The cities with the lowest violent crime rates tend to share several other socioeconomic characteristics as well — notably, economic prosperity. Indeed, the vast majority of the cities on the list have a low unemployment rate and a high median household income,” authors of the America’s Safest Cities report said.

Here are the top 10 safest cities in the United States:

1. Irvine, California
2. Naperville, Illinois
3. Murrieta, California
4. McAllen, Texas
5. Frisco, Texas
6. Gilbert, Arizona
7. Pearland, Texas
8. Thousand Oaks, California
9. Glendale, California
10. League City, Texas